Question 989800
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I corrected your problem:


Train A leaves the station traveling a constant 35 miles per hour. One hour later, Train B leaves the station traveling a constant 45 miles per hour 

<U>and moves in the same direction</U>. Neither train slows down, speeds up, or stops. How long will it take for Train B to catch up to Train A?
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<B>Solution</B>


When the train &nbsp;B&nbsp; starts moving, &nbsp;it is &nbsp;35&nbsp; miles behind the train &nbsp;A.


The speed of the train B is in 10 miles per hour greater than that of the train A. Hence, it will take &nbsp;{{{35/10}}} = 3.5 &nbsp;hours for the train &nbsp;B&nbsp; to catch the train &nbsp;A.


For similar Travel and Distance problems see the lesson &nbsp;<A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>&nbsp; in this site.