Question 84663
Let the width be X
and then let the Length be Y

so if length is 3 less than width
then Y = X - 3

perimeter = 62 

so as per the formula-
perimeter = 2(w X h) = 2(X X Y)
so 62 = 2(X(X - 3))
62 = 2(x^2 - 3x)
62 = 2x^2 - 6x
2x^2 - 6x - 62=0 

So after this we have  *[invoke quadratic "x", 2, 6, -62]

Let me know if this works for you.