Question 989725

The formula you will use is {{{y = (kx)/z}}}


Plug in the values for z = 36 when x = 3 and y = 2 then solve:


{{{2 = (k(3))/36}}}  --> {{{2 = 3k/36}}}


{{{36*2 = (3k/36)*36}}}


{{{72 = 3k}}}


{{{72/3 = (3k)/3}}}


{{{k = 24}}}