Question 84670
x^2 - x - 6 > 0

==> x^2 - 3x + 2x - 6 > 0

==> x(x-3) + 2(x-3) > 0

==> (x-3)(x+2) > 0

This is true only when x>3  or when x < -2

==> the solution is (-infinity, -2) U (3, infinity)