Question 989588
<table cellpadding=5><tr><td>4i^3-2i^2+1</td><td></td></tr><tr><td>4i^2*i-2i^2+1</td><td>Break up i^3 into i^2*i</td></tr><tr><td>4(-1)*i-2(-1)+1</td><td>Use the fact that i^2 = -1</td></tr><tr><td>-4*i+2+1</td><td></td></tr><tr><td>-4i+3</td><td></td></tr><tr><td>3-4i</td><td></td></tr></table>

We're now in standard form a+bi where a = 3, b = -4