Question 989526
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Perpendicular lines have slopes that are negative reciprocals of each other, so you can determine the slope of your desired line by calculating the slope of your given line and you have a given point. The slope of a line where the equation is given in standard form, *[tex \Large Ax\ +\ By\ =\ C], is given by *[tex \Large -\frac{A}{B}], hence the slope of the perpendicular is *[tex \Large \frac{B}{A}].


Use the Point-Slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \