Question 84632
X*X=4X+32
{{{x^2 = 4x + 32}}}


Because this has an {{{x^2 }}} in the problem, it is a QUADRATIC EQUATION, and you must first set it equal to zero:
{{{x^2 -4x -32=0}}}


Next, factor it:
{{{x^2 = 4x + 32}}}
{{{(x-8)(x+4)=0 }}}


Now, set each factor equal to zero:
{{{x-8=0}}} or {{{x+4=0}}}

{{{x=8}}} or {{{x=-4}}}


R^2 at SCC