Question 989376
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Add *[tex \Large x] to both sides.


Factor *[tex \Large y] out of the LHS expression.


Multiply both sides by the reciprocal of the binomial coefficient on *[tex \Large y].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \