Question 989364
The z-value for 95% confidence is +/-1.96
z*sqrt{ p*(1-p)/n} =0.03
square both sides and multiply both by n,
z^2*p/(1-p)=0.0009n
3.8416*0.32*0.68=0.0009n
n=929 rounded up.
No preliminary estimate, and one uses 0.5 as the maximum sample size.
3.846*0.5*0.5=0.0009n
n=1068 rounded up.