Question 989367
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Since the null set has no elements, it certainly doesn't have any elements that are themselves sets, and so the set which has as a single element the null set cannot be a subset of the null set.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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*[tex \LARGE \ \ \ \ \ \ \ \ \ \