Question 989353
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This really isn't a math problem.  It is a pay careful attention to what you read problem.


Let *[tex \Large x] represent the amount she started with.  Then *[tex \Large x\ -\ 25] is the amount she had after she got her hair cut.  Then *[tex \Large \frac{x\ -\ 25}{5}] is the amount she loaned to her friend, and we now have that the amount she had before she stopped at the bank was:  *[tex \Large x\ -\ 25\ -\ \frac{x\ -\ 25}{5}].  She deposited *[tex \Large \frac{2}{3}\left(\frac{x\ -\ 25}{5}\right)].  Hence, after the bank she had *[tex \Large x\ -\ 25\ -\ \frac{x\ -\ 25}{5}\ -\ \frac{2}{3}\left(\frac{x\ -\ 25}{5}\right)].  And this amount is equal to $40, so 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ -\ 25\ -\ \frac{x\ -\ 25}{5}\ -\  \frac{2}{3}\left(\frac{x\ -\ 25}{5}\right)\ =\ 40]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \