Question 989339

 {{{S = sqrt(h M) / 6}}}

{{{S = (1/6)sqrt(h M) }}}

Since height is constant, differentiate with respect to mass:

{{{dS = (1/6)(1/2)dM/sqrt(hM) = dM/(12sqrt(hM))}}}

{{{dS/dt = (dM/dt)/(12sqrt(hM))}}}

{{{M = 71kg}}}
{{{h = 187cm}}}=>{{{h = 1.87m}}}

{{{dM/dt = -3.1(kg/month)}}}


{{{dS/dt = -3.1/(12sqrt(1.87*71))}}}

{{{dS/dt = -3.1/(12sqrt(132.77))}}}

{{{dS/dt = -3.1/(12*11.52258651518833)}}}

{{{dS/dt = -3.1/(138.27103818226)}}}

{{{dS/dt = -3.1/(138.27103818226)}}}

{{{dS/dt =-0.0224(m^2/month)}}}