Question 84633
find three consecutive integers 
:
x, (x+1), (x+2)
:
whose sum is four times the greatest integer
x + (x+1) + (x+2) = 4(x+2)
x + x + 1 + x + 2 = 4x + 8
3x + 3 = 4x + 8
3x - 4x = 8 - 3
-x = +5
x = -5
:
The integers: -5, -4, -3
:
Check:
 -5 + (-4) + (-3) =
- 5 - 4 - 3 = -12