Question 989243


{{{2 + 2x - x^2 = 0}}} swap the sides

{{{0=x^2-2x -2}}} 

coefficients are: {{{a=1}}},{{{b=-2}}}, and {{{c=-2}}}

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

{{{x = (-(-2) +- sqrt( (-2)^2-4*1*(-2) ))/(2*1) }}} 

{{{x = (2 +- sqrt( 4+8))/2 }}}

{{{x = (2 +- sqrt( 12))/2 }}}

{{{x = (2 +- sqrt( 4*3))/2 }}}

{{{x = (2 +- 2sqrt( 3))/2 }}}

{{{x = (cross(2)1 +- cross(2)1sqrt( 3))/cross(2)1 }}}

{{{x = (1 +- sqrt( 3)) }}}

exact solutions:

{{{x = (1 + sqrt( 3)) }}}

{{{x = (1 - sqrt( 3)) }}}

approximate:


{{{x = (1 + 1.73) }}}=>{{{x = 2.73 }}}

{{{x = (1 - 1.73) }}}{{{x = -0.73 }}}



{{{drawing( 600, 600, -10, 10, -10, 10,
circle(2.73,0,.12),circle(-0.73,0,.12),
 graph( 600, 600, -10, 10, -10, 10, x^2-2x -2)) }}}