Question 989149
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The perpendicular forms a right triangle with hypotenuse AB=2cm,
one leg is 1/2(BC)=1cm.
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Let c=AB=2cm, b=1/2(BC)=1cm, a=perpendicular distance from A to BC
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{{{a^2+b^2=c^2}}}
{{{a^2=c^2-b^2}}}
{{{a=sqrt(c^2-b^2)}}}
{{{a=sqrt((2cm)^2-(1cm)^2)}}}
{{{a=sqrt(4cm^2-1cm^2)}}}
{{{a=sqrt(3cm^2)}}}
{{{a=sqrt(3)cm}}}
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ANSWER: The perpendicular distance is {{{sqrt(3)cm}}}.