Question 989217
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If *[tex \Large a] is a zero of a polynomial, then *[tex \Large (x\ -\ a)] is a factor of the polynomial.  Since rational zeros can be singular, you don't have to consider conjugate factors.


Expand *[tex \Large (x\ -\ 5)(x\ -\ 9)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \