Question 989110
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x^2\ -\ 24\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 8\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ \sqrt{8})(x\ +\ \sqrt{8})\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \sqrt{8}]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -\sqrt{8}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \