Question 989096
Let {{{ x }}} = % concentration of the 1st solution
{{{ 2x }}} = ml of acid in 1st solution
{{{ .85*3 }}} = ml of acid in 2nd solution
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{{{ ( 2x + .85*3 ) / ( 2 + 3 ) = .79 }}}
{{{ 2x + .85*3 = .79*5 }}}
{{{ 2x = .79*5 - .85*3 }}}
Solve for {{{ x }}}
( I misplaced my calculator )