Question 988875

{{{((-2)^(-3) - 3)/((-3)^(-2)-3^0 )}}}


recall the rules: {{{a^(-m)=1/a^m}}} and {{{a^0=1}}}


so, you have:


{{{((-2)^(-3) - 3)/((-3)^(-2)-3^0 )}}}....apply rules


{{{(1/(-2)^3 - 3)/(1/(-3)^2-1 )}}}.....{{{(-2)^3=(-2)(-2)(-2)=-8}}}


{{{(1/(-8) - (3*8)/8)/(1/9-1 )}}}


{{{(-1/8 - 24/8)/(1/9-9/9 )}}}


{{{(-25/8)/(-8/9 )}}}...........use the rule {{{(a/b)/(c/d)=ad/bc}}}


{{{(-25*9)/(8(-8) )}}}


{{{(-225)/(-64)}}}


{{{3.515625}}}.........round it to two decimal places


{{{3.52}}}