Question 988527
{{{-3/(4-i)=-3/(4-i)*((4+i)/(4+i))}}}
{{{-3/(4-i)=(-12-3i)/(16+4i-4i-i^2)}}}
{{{-3/(4-i)=(-12-3i)/(16+1)}}}
{{{-3/(4-i)=(-12-3i)/17}}}
{{{-3/(4-i)=-12/17-(3/17)i}}}