Question 988382
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You say you started at the point (0,5).  Why did you start there?  The *[tex \Large y]-intercept is *[tex \Large \left(0,\frac{28}{5}\right)], which is to say *[tex \Large (0,5.6)]


The point (-5,8) is NOT on your line.  You know that because  *[tex \Large f(-5)\ =\ -\frac{3}{5}(-5)\ +\ \frac{28}{5}\ \not{=}\ 8].  I'll leave it to you to verify the arithmetic.


On the other hand, (-4,8) IS on the line.  Again, I'll leave the arithmetic to you.


Rather than start at the intercept, the person who came up with the textbook solution began at the nearest point to the *[tex \Large y]-intercept that had integer coordinates, specifically the point (1,5).  I think if you go up 3, left 5 from that point you will find yourself at (-4,8).


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \