Question 84539
1.
*[invoke completing_the_square 3, 0, 4]


2.
*[invoke completing_the_square 3, 6, -17]


3.
Since the equation {{{y=3(x+1)^2-20}}} is already in vertex form, the equation of the axis of symmetry is {{{x=-1}}} and the vertex is (-1,-20). Remember, any equation in vertex form {{{y=a(x-h)^2+k}}} has an axis of symmetry of {{{x=h}}} and a vertex of (h,k)



4.
*[invoke completing_the_square 1, 2, 0]