Question 988278
{{{(2-3i)(1-i)-(3-i)(3+i) =(2-2i-3i+3i^2)-(9+3i-3i-i^2)}}}
 {{{(2-3i)(1-i)-(3-i)(3+i) =(2-5i-3)-(9+1)}}}
 {{{(2-3i)(1-i)-(3-i)(3+i) =(-1-5i)-(10)}}}
 {{{(2-3i)(1-i)-(3-i)(3+i) =-11-5i}}}