Question 988208
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The perimeter of a rectangle is two times the length plus two times the width.  Therefore, the sum of the length and the width is one-half of the perimeter.  Your length is 3 less than 4 times the width, so if the width is *[tex \Large w] then the length has to be *[tex \Large 4w\ -\ 3].  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  w\ +\ 4w\ -\ 3\ =\ 17]


Solve for *[tex \Large w] and then calculate *[tex \Large 4w\ -\ 3]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \