Question 988181

How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid solution to obtain a 22% sulfuric acid solution? 
<pre>Let amount of water be W
</pre>Solve using any of the two equations:
<b><u>
Equation 1</b></u><pre>0W + .34(26) = .22(W + 26)
        8.84 = .22W + 5.72
        .22W = 8.84 - 5.72
        .22W = 3.12
Solve for W, the amount of water
</pre>
OR


<b><u>Equation 2</b></u><pre>W + .66(26) = .78(W + 26)
  W + 17.16 = .78W + 20.28
   W - .78W = 20.28 - 17.16
       .22W = 3.12
Solve for W, the amount of water</pre>