Question 988192
<font face="Times New Roman" size="+2">


Let *[tex \Large x] represent the length of the smallest piece.  Then *[tex \Large x\ +\ 5] is the length of the middle piece and *[tex \Large x\ +\ 9] is the length of the longest piece.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ (x\ +\ 5)\ +\ (x\ +\ 9)\ =\ 59]


Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 5] and *[tex \Large x\ +\ 9]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \