Question 988185
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Let *[tex \Large x] represent the number of calories in the breakfast meal.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ (x\ +\ 69)\ +\ 2x\ +\ 119\ +\ 89\ =\ 1925]


Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 69] and *[tex \Large 2x].



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \