Question 988089
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt[3]{16x^4y}\ -\ 3x\sqrt[3]{2xy}\ +\ 5\sqrt[3]{-2xy^4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt[3]{8x^3}\sqrt[3]{2xy}\ -\ 3x\sqrt[3]{2xy}\ +\ 5\sqrt[3]{-y^3}\sqrt[3]{2xy}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\sqrt[3]{2xy}\ -\ 3x\sqrt[3]{2xy}\ -\ 5y\sqrt[3]{2xy}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(2x\ -\ 3x\ -\ 5y\right)\sqrt[3]{2xy}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(-x\ -\ 5y\right)\sqrt[3]{2xy}]


Note the sign change in the second step because *[tex \Large \sqrt[3]{-1}\ =\ -1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \