Question 988089
I am going to assume that 16x^4y is 16*x^4 *y.
Cube root of 16 is 2*2 ^1/3 (cube root of [8*2]
Term 1: 2*2^1/3 {x^4/3*y*1/3}
Term 2: -3*2^1/3 *x^(1/3)*y^(1/3)
Term 3: +5 *-2^1/3*x^1/3*y^4/3
;
common terms
2^1/3.  That is multiplied by (2-3-5) 
x^1/3.  that is multiplied by (x)
y^1/3.  That is multiplied by (y)
;
in front: 2^(1/3)*x^(1/3)*y^(1/3)* {2x-3-5y}