Question 988090
Put them all into the form of y=mx+b and compare m.
first is y=-4x-4
second is -2y=-8x-2; divide by -2; y=4x+1
third is y=4x+8
;
Same slopes, different intercepts, parallel.
Different slopes, which when multiplied together are not -1: neither.  If multiplication of slopes is -1, then the lines are perpendicular.  That is all you have to do.
The second and third have the same slope, so they are parallel.  The first has a slope of -4, but since -4*4=-16 and not -1, they intersect and are not perpendicular.

{{{graph(300,200,-10,10,-10,10,-4x-4,4x+1,4x+8)}}}