Question 988025
At the x-intercepts, {{{ y = 0 }}}, so
{{{ 2x^2 - 10x + 5 = 0 }}}
Use the quadratic formula
{{{ x = ( -b +- sqrt( b^2 - 4*a*c )) / (2*a) }}}
{{{ a = 2 }}}
{{{ b = -10 }}}
{{{ c = 5 }}}
{{{ x = ( -(-10) +- sqrt( (-10)^2 - 4*2*5 )) / (2*2) }}}
{{{ x = ( 10 +- sqrt( 100 - 40 )) / 4 }}}
{{{ x = ( 10 +- sqrt( 60 )) / 4 }}}
{{{ x =  5/2 +- sqrt(15 )/2 }}}
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Check answers:
{{{ x = 2.5 + 3.873/2 }}}
{{{ x = 2.5 + 1.936 }}}
{{{ x = 4.436 }}}
and
{{{ x = 2.5 - 3.873/2 }}}
{{{ x = 2.5 - 1.936 }}}
{{{ x = .564 }}}
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{{{ 2*4.436^2 - 10*4.436 + 5 = 0 }}}
{{{ 2*19.678 - 44.36 + 5 = 0 }}}
{{{ 39.356 - 44.36 + 5 = o }}}
{{{ -5.004 + 5 = 0 }}}
close enough- you can check the other x-intercept