Question 987898
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Presuming that the 6th test is of equal weight to the first 5, that is, the 6th test isn't a final exam that counts as two tests or some other such scheme, then the total score for all 6 tests must be 6 times 81 in order to have an average of 81.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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