Question 987888
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Factor the numerator:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ xy\ -\ 5x\ +\ 2y\ -\ 10]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (xy\ -\ 5x)\ +\ (2y\ -\ 10)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(y\ -\ 5)\ +\ 2(y\ -\ 5)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 2)(y\ -\ 5)]


Using a similar process, factor the denominator.  If you find a factor common to both numerator and denominator, you can eliminate the factor from both numerator and denominator.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \