Question 987891
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\ \times\ 3\ =\ 6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3\ \times\ 4\ =\ 12]


...


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n(n\ +\ 1)\ =\ n^2\ +\ n]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \