Question 987716
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The ends of the pile are not defined.
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a) There are two face sizes. Since ends are not defined, neither can be excluded.
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{{{Face[1]=(14in*14in)(1ft^2/144in^2)}}}={{{1.36ft^2}}}
{{{Face[2]=(14in*15in)(1ft^2/144in^2)}}}={{{1.46ft^2}}}
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b)
There are two 14in x 14in faces and four 15in x 14in faces:
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{{{Surface area=(2(Face[1])+4(Face[2]))(0.0929m^2/1ft^2)}}}
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{{{Surface area=(2(1.36ft^2)+4(1.46ft^2))(0.0929m^2/1ft^2)}}}
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{{{Surface area=(2.72ft^2+5.84ft^2)(0.0929m^2/1ft^2)}}}
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{{{Surface area=(8.56ft^2)(0.0929m^2/1ft^2)}}}
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{{{Surface area=0.795m^2}}}
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ANSWER: The surface area is 0.795 square meters. 
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c)
Volume=L x W x H=(14in)(14in)(15in)(1.64*10^-5m^3)/1in^3
Volume=(2940in^3)((1.64*10^-5m^3)/1in^3)=4.82*10-2m^3
ANSWER The volume is 0.0482 cubic meters.