Question 987697
Use the rule:
{{{ log(a) - log(b) = log( a/b ) }}}
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{{{ log( x+1 ) - log( x-1 ) = log( 3 ) }}}
{{{ log ( ( x+1 ) / ( x-1 ) ) = log (3) }}}
{{{ ( x+1 ) / ( x-1 ) = 3 }}}
{{{ x + 1 = 3*( x-1 ) }}}
{{{ x + 1 = 3x - 3 }}}
{{{ 2x = 4 }}}
{{{ x = 2 }}}
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check:
{{{ log( x+1 ) - log( x-1 ) = log( 3 ) }}}
{{{ log( 2+1 ) - log( 2-1 ) = log( 3 ) }}}
{{{ log( 3 ) - log( 1 ) = log( 3 ) }}}
{{{ log( 3 ) - 0 = log( 3 ) }}}
{{{ 3 = 3 }}}
OK