Question 987649
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"...changes by an amount..." is non-specific.  Did the measure of the edge of the cube get larger or smaller?  Either one is a change, and the amount specified is a positive number does not alter the ambiguity.  "approximate" without a specification of required precision is non-specific.  "A little bit bigger (or smaller)" is an unassailably correct answer to this question as posed.


Be that as it may, the volume of a cube with edges that measure *[tex \Large x] units has a volume of *[tex \Large x^3] cubic units.  If the measure of the edge is increased by some value *[tex \Large h], then the new volume is *[tex \Large (x\ +\ h)^3\ =\ x^3\ +\ 3x^2h\ +\ 3xh^2\ +\ h^3], and the difference between the original volume and the new volume is *[tex \Large \Delta{V}\ =\ 3x^2h\ +\ 3xh^2\ +\ h^3].  Similarly, if the edge is decreased some value *[tex \Large h], then the new volume is *[tex \Large (x\ -\ h)^3\ =\ x^3\ -\ 3x^2h\ +\ 3xh^2\ -\ h^3], and the difference between the original volume and the new volume is *[tex \Large \Delta{V}\ =\ -3x^2h\ +\ 3xh^2\ -\ h^3].


Once you decide whether you are getting larger or smaller, you can plug your values of *[tex \Large x\ =\ 11] and *[tex \Large h\ =\ 0.01] into the appropriate expression for *[tex \Large \Delta{V}], do the arithmetic, and round to whatever precision you need or desire.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \