Question 987648
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First,  estimate the surface area of the tube.  Is is


{{{pi*r^2*L}}} = {{{3.14*0.05^2*11}}} = 0.08635 {{{m^2}}}.


To get the volume of the required insulation material,  multiply this surface area by the thickness of  1 mm = 0.001 m.  It gives you the answer:


0.08635*0.001 = 0.0008635 {{{m^3}}}. 


In cubic centimeters,  it is  {{{0.0008635*10^6}}} = 863.5 {{{cm^3}}}.