Question 987533
 given 3y<=4,2x+3y<=8, x>=3
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The vertical boundary is x = 3 and the area to the right of it.
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Horizontal boundaries are y <= 4/3 and y <= (-2/3)x + (8/3)
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{{{graph(400,400,-2,5,-2,5,(-2/3)x+(8/3),4/3)}}}
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Vertices of solution area:: (3,0.67),(3,0),(4,0)
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Cheers,
Stan H.
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