<PRE><B>Question 987645</B>
The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 23 cm^2, what is the length of the diagonal? 
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Length:: x
Width:: 2x-5
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x(2x-5) = 23
2x^2 -5x - 23 = 0
x = 4.86
2x-5 = 4.72
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Ans: diag = sqrt(4.86^2+4.72^2) = 6.77 cm
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Cheers,
Stan H.
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