Question 84465
    I am trying to find the inverse of each function and express it in the form y=f inverse -1(x). And I need to verify each result by showing that (f composed of f)(x)=f inverse -1 composed pf f)(x)=I(x). The problem to be solved is:
    x = 4y + 1
GENERALLY WE ARE GIVEN Y=F(X)=SOME FUNCTION OF X SAY Y=F(X)=4X+1...OR..SOME THING LIKE THAT THEN PROCEDURE IS 
PUT 
1.Y=4X+1
2.SOLVE FOR X
4X=Y-1
X=(Y-1)/4
3.NOW PUT X IN PLACE OF Y ON THE RIGHT SIDE AND THEN WE GET 
F INVERSE X =(X-1)/4 
TO CHECK
F OF [F INVERSE X] = X 
TO SIMPLIFY UNDERSTANDING AND FOR EASE OF WORK
PUT F INVERSE X =Z= (X-1)/4
F[F INVERSE X]=F[Z]= 4Z+1 =[4(X-1)/4]+1 = (4X-4+4)/4 = 4X/4=X
TO CHECK
F INVERSE OF [F(X)]=X
F INVERSE OF[4X+1] .....
TO SIMPLIFY UNDERSTANDING AND FOR EASE OF WORK....
PUT Z=4X+1
F INVERSE OF[Z]=(Z-1)/4 =[4X+1-1]/4=4X/4=X
HOPE YOU UNDERSTOOD 

BUT YOU GAVE 
X=4Y+1..........LET US FIND F INVERSE Y IN THE SAME MANNER
4Y=X-1
Y=(X-1)/4
HENCE
F INVERSE Y = (Y-1)/4