Question 987511

Graph the following equations using the slope ({{{m}}}) and the y-intercept({{{b}}}).

A. 
{{{-3x+4y=16}}}....write in slope-intercept form {{{y=mx+b}}}
{{{4y=3x+16}}}
{{{y=(3/4)x+16/4}}}
{{{y=(3/4)x+4}}}=> slope is {{{m=3/4}}} and y-intercept is {{{b=4}}}

so, we have one point, ({{{0}}},{{{4}}}) and we need one more point to graph a line

{{{x}}}|{{{y}}} 
{{{0}}}|{{{4}}}
{{{4}}}|{{{7}}}..{{{y=(3/4)4+4}}}=>{{{y=3+4}}}=>{{{y=7}}}

plot these two points and draw a line through:

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,4,.12), circle(4,7,.12),
locate(0.3,4,p(0,4)), locate(4,7,p(4,7)), 
 graph( 600, 600, -10, 10, -10, 10, (3/4)x+4)) }}}



B. 
{{{2y-3x=2}}}
{{{2y=3x+2}}}
{{{y=(3/2)x+1}}}

{{{x}}}|{{{y}}} 
{{{0}}}|{{{1}}}
{{{2}}}|{{{4}}}..{{{y=(3/2)2+1}}}=>{{{y=3+1}}}=>{{{y=4}}}

plot these two points and draw a line through:

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,1,.12), circle(2,4,.12),
locate(0.3,1,p(0,1)), locate(2,4,p(2,4)), 
 graph( 600, 600, -10, 10, -10, 10, (3/2)x+1)) }}}