Question 987460
x + 2 + 2x + 3 + 5x = 21  {perimeter of triangle is 21}
8x + 5 = 21 {combined like terms}
8x = 16 {subtracted 5 from each side}
x = 2 {divided each side by 8}


x + 2 = 4 {substituted 2, in for x, into x + 2}
2x + 3 = 7 {substituted 2, in for x, into 2x + 3}
5x = 10 {substituted 2, in for x, into 5x}


short side is 4
longest side is 10
intermediate side is 7
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