Question 987167
.
The width and length are legs of a right triangle, with the diagonal as hypotenuse.
.
W=width; L=length=2W; D=diagonal={{{4sqrt(5)}}}
.
{{{L^2+W^2=D^2}}}
{{{(2W)^2+W^2=(4sqrt(5))^2}}}
{{{4W^2+W^2=16(5)}}}
{{{5W^2=80}}}
{{{W^2=16}}}
{{{W=4}}}
.
ANSWER 1: The width is 4 meters.
.
L=2W=2(4 meters)=8 meters
.
ANSWER 2: The length is 8 meters