Question 987425
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The first thing you have to do is to decide exactly what the variable *[tex \Large x] represents.  Until you do that, nothing you do will make any sense.  So let's start with the first sentence of every word problem solution you will ever write:


"Let *[tex \Large x] represent..."


For this problem, I would suggest that you let *[tex \Large x] represent the width.


The next thing you need is to represent the length in terms of the width, in this case the variable *[tex \Large x].  The problem says that the length is 25 meters greater than the width.  Now what would you say is an expression involving *[tex \Large x] that is 25 larger than *[tex \Large x]?


Once you have the two expressions in *[tex \Large x], one to represent the width and one to represent the length, you can consider the formula for the perimeter of a rectangle.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


You are given the value of the perimeter, so you can plug that in.  We decided that the width is *[tex \Large x], so you can replace *[tex \Large w] with *[tex \Large x].  And then you can substitute the expression you derived to represent the length in place of *[tex \Large l].  You will end up with a linear equation in *[tex \Large x] that you can solve by ordinary means.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \