Question 987225
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For a linear equation of the form *[tex \Large y\ =\ mx\ +\ b], the slope is the coefficient on the variable.


The *[tex \Large y]-coordinate of the *[tex \Large y]-intercept is the constant term in *[tex \Large y\ =\ mx\ +\ b].  The *[tex \Large y]-intercept is the point *[tex \Large (0,b)].  This represents the value of the function when the input value is zero.


The *[tex \Large x]-coordinate of the *[tex \Large x]-intercept is the value of *[tex \Large x] that is required to make the value of the function be zero.  In the case of *[tex \Large y\ =\ mx\ +\ b], this value is *[tex \Large a\ =\ -\frac{b}{m}], and the *[tex \Large x]-intercept is then the point *[tex \Large (a,0)].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \