Question 987371
A way to start this can be
Let p be perimeter of the square;
Let 2pi*r be the circumference of the circle;
{{{p+2pi*r=360}}}.


{{{p/4}}} would be the side length of the square, and area is  {{{(p/4)^2}}}.


{{{pi*r^2}}} would be area of the circle.


This may be enough for you to continue on to figure the two lengths making up the original wire of length 360.