Question 987129
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x and x+2 are consecutive odd integers. x+4=next consecutive odd integer.
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{{{(x)(x+2)=(x+4)^2-58}}}
{{{x^2+2x=x^2+8x+16-58}}
{{{0=6x-42}}}
{{{0=x-7}}}
{{{7=x}}} 
ANSWER 1: the first integer is 7.
second integer=x+2=7+2=9
ANSWER 2: The second integer is 9.
third integer=x+4=7+4=11
ANSWER 3: The third integer is 11.
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CHECK:
{{{(7)(9)=(11)^2-58}}}
{{{63=121-58}}}
{{{63=63}}}