Question 987157
Using the derivative:
{{{dy/dx=8x-7}}}
Set the derivative equal to zero.
{{{8x-7=0}}}
{{{8x=7}}}
{{{x=7/8}}}
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.
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Using the vertex form:
Convert to vertex form,
{{{y=4(x^2-(7/4)x)+3}}}
{{{y=4(x^2-(7/4)x+(7/8)^2)+3-4(7/8)^2}}}
{{{y=4(x-7/8)^2+3-4(49/64)}}}
{{{y=4(x-7/8)^2+48/16-49/16}}}
{{{y=4(x-7/8)^2-1/16}}}
Vertex is ({{{7/8}}},{{{-1/16}}})