Question 987120
The faster car's time is:
{{{ t + 2 }}} hrs
The slower car's time is:
{{{ t }}} hrs
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The faster car's distance is:
{{{ d + 140 }}}
The slower car's distance is:
{{{ d }}}
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Faster car's equation:
(1) {{{ d + 140 = 50*( t + 2 ) }}}
Slower car's equation:
(2) {{{ d = 30t }}}
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Substitute (2) into (1)
(1) {{{ 30t + 140 = 50*( t + 2 ) }}}
(1) {{{ 30t + 140 = 50t + 100 }}}
(1) {{{ 20t = 40 }}}
(1) {{{ t = 2 }}}
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(2) {{{ d = 30t }}}
(2) {{{ d = 30*2 }}}
(2) {{{ d = 60 }}} mi
and
(1) {{{ d + 140 = 50*( t + 2 ) }}}
(1) {{{ d + 140 = 50*( 2 + 2 ) }}}
(1) {{{ d + 140 = 200 }}}
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The faster car travels {{{ 200 }}} mi
The slower car travels {{{ 60 }}} mi